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Advanced Math / Nonlinear functions Difficulty: Hard

The function f is defined by f(x)=(-8)(2)x+22. What is the y-intercept of the graph of y=f(x) in the xy-plane?

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Explanation

Choice A is correct. The y-intercept of the graph of y=fx in the xy-plane occurs at the point on the graph where x = 0 . In other words, when x = 0 , the corresponding value of fx is the y-coordinate of the y-intercept. Substituting 0 for x in the given equation yields f0=-820+22, which is equivalent to f0=-81+22, or f0=14. Thus, when x = 0 , the corresponding value of fx is 14 . Therefore, the y-intercept of the graph of y=fx in the xy-plane is 0,14.

Choice B is incorrect and may result from conceptual or calculation errors.

Choice C is incorrect and may result from conceptual or calculation errors.

Choice D is incorrect. This could be the y-intercept for fx=-82x, not fx=-82x+22.